Given two strings s and t, return true if s is a subsequence of t, or false otherwise.
A subsequence of a string is a new string that is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (i.e., “ace” is a subsequence of “abcde” while “aec” is not).
Example 1:
Input: s = "abc", t = "ahbgdc"
Output: true
Example 2:
Input: s = "axc", t = "ahbgdc"
Output: false
class Solution(object):
def isSubsequence(self, s, t):
"""
:type s: str
:type t: str
:rtype: bool
"""
stack = list(s[::-1])
for i in t:
# if stack is not empty, and compare the last element to i
if stack and i == stack[-1]:
stack.pop()
return not stack
class Solution(object):
def isSubsequence(self, s, t):
i, j = 0, 0 # Two pointers for s and t
while i < len(s) and j < len(t):
if s[i] == t[j]:
i += 1 # Match found, move the s pointer
j += 1 # Always move the t pointer
return i == len(s) # True if all characters in s are matched