Given a string s, reverse only all the vowels in the string and return it.
The vowels are ‘a’, ‘e’, ‘i’, ‘o’, and ‘u’, and they can appear in both lower and upper cases, more than once.
Example 1:
Input: s = "IceCreAm"
Output: "AceCreIm"
Explanation:
The vowels in s are ['I', 'e', 'e', 'A']. On reversing the vowels, s becomes "AceCreIm".
Example 2:
Input: s = "leetcode"
Output: "leotcede"
Constraints:
1 <= s.length <= 3 * 105
s consist of printable ASCII characters.
class Solution(object):
def reverseVowels(self, s):
"""
:type s: str
:rtype: str
"""
vowels = "aeiouAEIOU"
vowels = list(vowels)
s = list(s)
i = 0
j = len(s)-1
# i , j = 0, len(s) -1
while(i < j):
if s[i] in vowels and s[j] in vowels:
# swap
s[i], s[j] = s[j], s[i]
i += 1
j -= 1
elif s[i] not in vowels:
i += 1
elif s[j] not in vowels:
j -= 1
return "".join(s)
# vowels = ['a', 'A', 'e', 'E', 'i', 'I', 'o', 'O', 'u', 'U']
# my_vowels = []
# ans = ""
# for char in s:
# if char in vowels:
# my_vowels.append(char)
# for index,char in enumerate(s):
# if char in vowels:
# ans += str(my_vowels.pop())
# else:
# ans += str(char)
# return ans